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NEW DELHI (AP) — Emiliano Grillo took a four-stroke lead at the Indian Open after shooting 4-under 68 on Friday.
The Argentine had five birdies and a bogey, lowering his total to 11-under 133 for the tournament.
Shubhankar Sharma, who three days ago received a special invitation to play at the Masters, made a charge with an 8-under 64 — the best round of the day. He had nine birdies, including six on the last nine holes. His only bogey came on the par-4 seventh.
Sharma was 5 over after his first nine holes on Thursday.
Pablo Larrazabal (71) and Andrew Johnston (66) were tied for third at 6 under, one stroke behind Sharma.
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